fix insert link naturally

foodie_utils.py

@@ -607,25 +607,16 @@ def insert_link_naturally(summary, source_name, source_url):
         target_para = random.choice(eligible_paragraphs)
         sentences = re.split(r'(?<=[.!?])\s+', target_para.strip())
         
-        eligible_sentences = [(i, s) for i, s in enumerate(sentences) if i < len(sentences)-1 and s.strip()]
+        eligible_sentences = [(i, s) for i, s in enumerate(sentences) if s.strip()]
         if not eligible_sentences:
-            eligible_sentences = [(i, s) for i, s in enumerate(sentences) if s.strip()]
+            logging.error("No eligible sentences found for link insertion.")
+            return summary
         
         sentence_idx, sentence = random.choice(eligible_sentences)
         link_pattern = f'<a href="{source_url}">{source_name}</a>'
         
-        words = sentence.split()
-        if len(words) < 5:  # Ensure enough words for natural insertion
-            new_sentence = f"{sentence.rstrip('.')} according to {link_pattern}."
-        else:
-            split_point = random.randint(2, len(words)-3)  # Split further into the sentence
-            # Remove trailing punctuation from the first part and ensure proper grammar
-            first_part = ' '.join(words[:split_point]).rstrip(',')
-            second_part = ' '.join(words[split_point:]).lstrip(',')
-            new_sentence = f"{first_part} according to {link_pattern} {second_part}"
-            # Ensure the sentence ends with a period
-            if not new_sentence.endswith('.'):
-                new_sentence += '.'
+        # Insert the link at the end of the sentence
+        new_sentence = f"{sentence.rstrip('.')} according to {link_pattern}."
         
         sentences[sentence_idx] = new_sentence
         new_para = ' '.join(sentences)